## Binary Tree Preorder Traversal

### 描述

Given a binary tree, return the **preorder** traversal of its nodes' values.

For example:
Given binary tree `{1,#,2,3}`,

```
1
\
2
/
3
```

return `[1,2,3]`.

Note: Recursive solution is trivial, could you do it iteratively?

### 分析

### 栈

{% if book.java %}
```java
// Binary Tree Preorder Traversal
// 使用栈，时间复杂度O(n)，空间复杂度O(n)
class Solution {
public List preorderTraversal(TreeNode root) {
ArrayList result = new ArrayList<>();
Stack s = new Stack<>();
if (root != null) s.push(root);

while (!s.isEmpty()) {
final TreeNode p = s.pop();

if (p.right != null) s.push(p.right);
if (p.left != null) s.push(p.left);
}
return result;
}
}
```
{% endif %}

{% if book.cpp %}
```cpp
// Binary Tree Preorder Traversal
// 使用栈，时间复杂度O(n)，空间复杂度O(n)
class Solution {
public:
vector preorderTraversal(TreeNode *root) {
vector result;
stack s;
if (root != nullptr) s.push(root);

while (!s.empty()) {
const TreeNode *p = s.top();
s.pop();
result.push_back(p->val);

if (p->right != nullptr) s.push(p->right);
if (p->left != nullptr) s.push(p->left);
}
return result;
}
};
```
{% endif %}

### Morris先序遍历

{% codesnippet "./code/binary-tree-preorder-traversal-2."+book.suffix, language=book.suffix %}{% endcodesnippet %}

### 相关题目

* [Binary Tree Inorder Traversal](binary-tree-inorder-traversal.md)
* [Binary Tree Postorder Traversal](binary-tree-postorder-traversal.md)
* [Recover Binary Search Tree](recover-binary-search-tree.md)